3x+1=x^2+9

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Solution for 3x+1=x^2+9 equation: 



3x+1=x^2+9

We move all terms to the left:

3x+1-(x^2+9)=0

We get rid of parentheses

-x^2+3x-9+1=0

We add all the numbers together, and all the variables

-1x^2+3x-8=0

a = -1; b = 3; c = -8;
Δ = b2-4ac
Δ = 32-4·(-1)·(-8)
Δ = -23
Delta is less than zero, so there is no solution for the equation

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